created intermediate point line

[Mito125]

Good morning, I should create a frame for this exercise:I created the left part of the frame, then through the body transformation menu translated the part created to one meter away, I created a line by joining the points 1 and 3 indicated but I can not create the line that joins points 2 and 4 (similar 2 and 9). They are intermediate points but I can't figure out how to tell them. I am still here:Maybe I took the wrong way to draw the loom, maybe using the design modeler I can't do it. should you find the coordinates of all points and make a sheet with the coordinates? I think it's a little fucked up. Perhaps you should make the drawing on another cad? Thank you.

 

[volaff]

Bye.
to me the frame seems symmetrical compared to the half-board.
You could create half frame and mirror.
Maybe if you do it with solidworks and then it matters the step you do first.

 

[Mito125]

I'm following a book that they had suggested to me, I haven't come to the symmetries yet, so I think he wants me to proceed by completing the complete frame. I also did not understand the mirror mode of ansys. And I do not understand whether the beam 1-2-3 is a single body or whether to be considered as two beams 1-2 and 2-3.

 

[volaff]

It's a single corpo sec me

 

[Mito125]

the problem is that when I insert a point on a line, this is broken and made in two bodies. I'm not sure I modeled the frame properly.

 

[volaff]

in fact that is a unique body.

 

[Mito125]

I have not yet managed to realize this online structure through the modeldesigner... It's the only exercise left. . .

 

[volaff]

I'm sorry, but isn't it mandatory to break that line in two?
I imagine that you intend to create the axis line of your structure and then assign the appropriate section that, to the eye, will be circular.

 

[Mito125]

I must realize the frame that is in the first picture, only with drawing tools (no mirrors or things like that). I can't make this structure in design modeler, I can't find a snap at the middle point or anything like that... that is why a very simple structure is creating a moment of problems.. .

 

[Onda]

I don't understand why you don't break the line in two equals in order to put a point where you have the third line summit. then you just have to be sure that your elements share the same knot so as not to create a lability.
However, whenever you have an intersection, the beam must have a knot and then a keypoint if you draw the lines first. then you must be sure to make a merge of the matching knots, so as to eliminate lability.

 

[Mito125]

then breaking lines do not get differences in results? in this chapter is not specified, so I should not use concepts that have not been explained to me. the book I'm following is chen, I was recommended in another post. How do I know if it's labile? If it was labile under load you should disassemble everything.

 

[Onda]

On the contrary. If you don't break the lines in the connection point, you won't have to coincide with the knots and then the system doesn't work.
attention, as said before, is not enough coincidence, but it is necessary that the three or more lines share the same knot, so that there is rigidity and exchange of forces between the various rods.

 

[Mito125]

so to model it I should realize line 1-3 as two strokes 1-2 and 2-3? Same thing for 4-6? Do I make two traits 4-5 and 5-6? thinking about reality, those traits I see them as unique traits, i.e. 1-3 will be a single bar. That's where my confusion comes from.

 

[Onda]

That's right. every connection must end your line. otherwise you can't reach the different bars between them.
the fem transfers forces to knots. No knot, no load transfer.
therefore at each intersection between different bars there must be a keypoint, where then a knot is placed.
So you have to make a merge of the matching knots, so that the different bars share a knot, and not just coincidences.

 

[Mito125]

Maybe I did. I followed your advice. I designed on the xy plane the left side with the broken, I applied a body transformation to translating it one meter long z negative while preserving the starting body. I created a passing auxiliary plan for the body halfway. I put a point on this floor that was 0.5 meters from the sketch. I used lines from points to create the upper rod that connects the two parts, and always with the same tool I made the rods 2-5 and 2-9. I then entered the rectangular section as from exercise. This is the result, I hope I have not forgotten anything:In this case I enabled lines bodies before opening the designmodeler, I left 3d analysis instead. I hope I set it correctly.

 

[volaff]

Bye.
I did it myself.
Could you compare the deformed?
just for curiosity!

 

[Mito125]

Hi volaff, I didn't save the various exercises, excuse me?

 

[volaff]

Okay.
it was right for.
I'm doing a mix of exercises between that book, udemy courses and more.
See you soon!