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load distribution on hexagonal structure

  • Thread starter Thread starter xLOGANx
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xLOGANx

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Good morning, everyone.

I wanted to ask you, explanations about a doubt about a structure. in detail, it is a cover made of steel elements and pvc tel. leaving the latter, the steel skeleton is a hexagon inscribed in a 10 m diameter circle; it has 6 2,2 m tall pillars while the structure has a total height of 4 m.
the 6 diagonals connect the pillars to a central element and are about 5.3 m long; the pillars are connected to each other by 5 m long beams (i.e. the side of the hexagon inscribed in the circle of 10 m of diameter).

the load that will act on the cover sheet (direct according to gravity) is 200 n/m^2.

in order to properly measure the structural elements, I considered it appropriate to define a load per unit length (to be applied to each single beam); the reasoning I followed is this:

- surface area calculation cover: 70 m^2 (calculated by multiplying the area of a single triangle forming the sheet for 6 elements)

- calculation of concentrated load on cover: 14000 n (i.e. 200 n/m^2 * 70 m^2)

- calculation of the concentrated load on diagonals and beams: 1167 n (i.e. 14000 n / 12 rods -> (6 traverses + 6 diagonals)))

- calculation of the load distributed on the single diagonal: 220 n/m (i.e. 1167 n / 5,3 m)

- calculation of the load distributed on the single traverse: 233.4 n/m (i.e. 1167 n / 5 m)

is it correct to have reasoned like this?

Thank you.
 
I would check it with a fem because surely the distributed load will not really be distributed and will be in the center. Of course that in first approximation could also go well, if you do not have a verification safety coefficient of 1,1.
You may also consider diagonals as lean or framed beams and overlapping effects. definitely your approach is the fastest.
 

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