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ungrained wheels

CristianT

Guest
Good evening to all,

I would have a doubt that I couldn't find answers.

with a 2.5 module, we have:
- a moving wheel m
- toothed wheel b (z=24)
- toothed wheel (z=29)

imagining to connect the 1st block with the 2nd as in figure, I have special conditions for the toothed wheel c?
i.e., in addition to having the same module and tangent primitive diameters, for the engraving of this closed circuit, do I have any condition to respect on the number of teeth of the wheel c or on the positioning or anything else that escapes me?

thanks to everyone in advance.

cristian.
 

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without a doubt any gear only and exclusively with a gear having the same module. We use the idiotic demonstrations that are on some books that leave saying "we imagine having two different modules".
it is necessary to verify that the interaxis are compatible and also the rotation senses. ...what I did down hereImmagine~2.pngSurely it will be to look at the teething otherwise you do not find yourself to gear, especially if you impose an imposed pattern.
the fact of having equal or odd teeth number could change a little geometry... and not only.

you could search on this forum and on khk gear the explanations for the epicloid gearboxes...... will help you find the raid.
 
hi mechanics mg there is something that does not return to me already from the first two toothed wheels, to turn in that sense the first wheel b if the m is the drive and turns in anticlockwise the ingrain and makes it rotate in the opposite direction
1605075701009.webp
 
hi mechanics mg there is something that does not return to me already from the first two toothed wheels, to turn in that sense the first wheel b if the m is the drive and turns in anticlockwise the ingrain and makes it rotate in the opposite direction
View attachment 59914
you are right, if a wheel clockwise the conjugate wheel counterclockwise. .
 
Hey, guys.
I did not put the real rotation of the wheels because in my question it did not come into this, in the sense that in theory there should be no doubt or anyway should not enter the speech.
for the rest there's something I miss. If I put a c wheel with odd teeth, for example equal to the a wheel, would it work? I have some doubts.
thanks anyway to everyone.
 
Why wouldn't that work? the number of teeth depends only on the transmission reports you want to get and any interattentions to comply, while the module depends on the power that the system has to transfer! Let me know if I missed something from your question.
 
Why wouldn't that work? the number of teeth depends only on the transmission reports you want to get and any interattentions to comply, while the module depends on the power that the system has to transfer! Let me know if I missed something from your question.
There is a risk that one or more pairs of toothed wheels are working against tooth instead of tooth.
 
Good evening to all,

I would have a doubt that I couldn't find answers.

with a 2.5 module, we have:
- a moving wheel m
- toothed wheel b (z=24)
- toothed wheel (z=29)

imagining to connect the 1st block with the 2nd as in figure, I have special conditions for the toothed wheel c?
i.e., in addition to having the same module and tangent primitive diameters, for the engraving of this closed circuit, do I have any condition to respect on the number of teeth of the wheel c or on the positioning or anything else that escapes me?

thanks to everyone in advance.

cristian.
but is there a particular reason why the wheel c should gear with two wheels b above and two below? talking only about cinematisms the system works well even if the wheel integrates with only one wheel b above and one below. I wouldn't trust mechanical work. Small processing errors would be enough to create strong overloads on the teeth.
 
Why wouldn't that work? the number of teeth depends only on the transmission reports you want to get and any interattentions to comply, while the module depends on the power that the system has to transfer! Let me know if I missed something from your question.
I ask why in the construction phase of an external company, they had problems in the installation.
 
but is there a particular reason why the wheel c should gear with two wheels b above and two below? talking only about cinematisms the system works well even if the wheel integrates with only one wheel b above and one below. I wouldn't trust mechanical work. Small processing errors would be enough to create strong overloads on the teeth.
I understand exactly what you say, even because that's what I would do. In the case of a figure instead, it is as if I had a hyperstatic system and perhaps problems could arise that escape first glance.
I put this configuration precisely because it reflects the problem that I have before my eyes to facts completed and sincerely I think there is something that I miss.
Thank you all.
 
Hey, guys.
I did not put the real rotation of the wheels because in my question it did not come into this, in the sense that in theory there should be no doubt or anyway should not enter the speech.
for the rest there's something I miss. If I put a c wheel with odd teeth, for example equal to the a wheel, would it work? I have some doubts.
thanks anyway to everyone.
If the wheel is the m the transmission ratio of the system is given by b/m, the wheels a and c are oziose and do not affect the transmission ratio, all the wheels will b turn with the same number of turns. See if I'm wrong. . .
 
I ask why in the construction phase of an external company, they had problems in the installation.
I don't understand, if the calculations of the interaxes are accurate you shouldn't have any mounting problems, unless for some reason the exit shafts must be in phase with some mechanism so if you are using pickups with sticks or grooved trees these processes should be done properly aligning them to the teeth, or if possible, it would be better to use calettators. Sorry the question, is it a multiple puncture head?
 
I ask why in the construction phase of an external company, they had problems in the installation.
as he said @meccanicamg It's a problem that has people who build epicloid ruotisms. I remember studying how to do it at university, but many years have passed and I have to finish urgent work. try to google the theoretical tracing and then return it to your real case.
 
There is a risk that one or more pairs of toothed wheels are working against tooth instead of tooth.
observing the system well the risk is there... and as said the ideal would be that you only fill it with a wheel above and with a wheel below.
 
If there is no technical reason why the gears should be all in cascading socket, you can predict the b series on the left on a different plane increasing the thickness of the gears to, so that you only integrate on the right gears (motor side). the rotations and synchronisms of the system do not change and avoid interference problems between the teeth.
 
the link to the discussion of epicicloidali on the forum are qui....qui....
while the manual khh is qui.
certainly the idea of having double-ended gears and working only one gear with one conduit I would say that is the optimal condition.
we build a patented machine that has practically a system of gears that close on themselves. it is essential to have some gears to today nterasse variable to manage the game of ungracing.
important mixing with related organs.
Surely it will be necessary that all the teeth are rectified and that they have enough game but it is not enough because it is almost impossible that you can get everything in contact....super lappature and very exact geometries.
 
if c has number of teeth different from to you will have problems of "phase" between the two wheels b and c.
in fact the wheels b are between them in phase thanks to a.
If there is a number of teeth different from then you will not be able to have the right mix because with a primitive of c different from that of a you will not be able to respect the angle step of the wheel c since you have two tangency points and a finite number of teeth to "make us stand".....the only possible solution assigned a module is that c=a.
This problem does not arise with single gear cascading trains but in your case it becomes fundamental.
greetings
 
If the wheel is the m the transmission ratio of the system is given by b/m, the wheels a and c are oziose and do not affect the transmission ratio, all the wheels will b turn with the same number of turns. See if I'm wrong. . .
It should be like that.
 
I don't understand, if the calculations of the interaxes are accurate you shouldn't have any mounting problems, unless for some reason the exit shafts must be in phase with some mechanism so if you are using pickups with sticks or grooved trees these processes should be done properly aligning them to the teeth, or if possible, it would be better to use calettators. Sorry the question, is it a multiple puncture head?
no, it is a screw-up system in an injection mold.
 

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