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exercise - drawing of machines (reducer)

  • Thread starter Thread starter iolupe
  • Start date Start date
Why have you marked me the white lines, are those of the hole or not? look I did so in the other design

but let me understand better you can fall from above blessed trees already mounted yes or no?
:biggrin:
If you could do the scans that you understand something, you don't have to understand the drawings.

can be mounted from above. what you have posted now you mount axial everything
 
the representation of the helical wheels, since I was asked is the one here attached.
Snow32 said:
...I came across a test simulation where I had a two-shaft gearbox set at 90 degrees. I was required to use cylindrical helical wheels. How do I represent them? does one actually not end up behind the other tree when they dissect?
 

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all those things fall axially. It's always the same story. you think that's half a gearbox and that there's the other half on it. But I don't think that's the plan of division. However, not knowing what the plan of division is because sti gearboxes never teach them in full, I would say that the crates should be sampled (all except trees and bearings). and all the mechanical organs are soaring not to come down from above!

if it were really half case, the fixing holes and the reference plugs are missing. and however the design must be fixed.

I ask the question: You can draw it like a decent rotary seal on a serious lid? :biggrin:

I marked you a pair of white lines that you cancel... Then the rest decide what to do.
So if I didn't mount the brace, the cylindrical roller bearings, I put example those nj and I blocked only the inside of the ring, is it correct? :smile:
 
very kind meccanicmg and available as always. only on the exercise ask me cylindrical wheels and trees to 90, not conical... I knew them:
 
mechanical excusesmg, last my petulent question: if the axles instead of parallels as in the pictures were orthogonal, to 90 degrees, how do the two wheels gear?
 
mechanical excusesmg, last my petulent question: if the axles instead of parallels as in the pictures were orthogonal, to 90 degrees, how do the two wheels gear?
cylindrical wheels with helical toothing are used, with a 45° angle of the propeller.

greetings
Mar
 
mechanical excusesmg, last my petulent question: if the axles instead of parallels as in the pictures were orthogonal, to 90 degrees, how do the two wheels gear?
gear at any angle, i.e. you have tree angle 90, but you can do it at any angle and always gear in the same way, depends on the angle of the propeller. if you have 90° of trees you have 45° of propeller.

I would say that at this point you should buy some manuals.... it is not possible that you become an engineer so through forums and randomly enclosed material. I recommend vademecum for designers and hoepli technicians.
 
I would say that at this point you should buy some manuals.... it is not possible that you become an engineer so through forums and randomly enclosed material. I recommend vademecum for designers and hoepli technicians.
:finger::finger::finger:

I would add, between the serious and the face and with a sarcastic humor tip, that the manual after taking it goes read, understood and frequently consulted... :tongue:
 

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