oleodynamic project

[pierop85]

Hello I would need advice from anyone who knows more than me, I should build a facilitator for the harvesting of vegetables, my idea is to mount two hydraulic motors on the two wheel wheels, commanded by two distributors connected in series, since I wanted to connect the engines directly to the wheels, I need the speed to be low, so I thought to connect everything in this way: from the pump to the maximum valve, then to a tap to reduce the flow. My doubt is diminishing the flow, to make less turns to the engines, can they move the plane? full load we are max 500kg. What engine displacement do I need?

 

[Planetary83]

missing some type data:

What speed range do you need?
Wheel diameter?
which total flow available and pressure?

 

[MBT]

Hello I would need advice from anyone who knows more than me, I should build a facilitator for the harvesting of vegetables, my idea is to mount two hydraulic motors on the two wheel wheels, commanded by two distributors connected in series, since I wanted to connect the engines directly to the wheels, I need the speed to be low, so I thought to connect everything in this way: from the pump to the maximum valve, then to a tap to reduce the flow. My doubt is diminishing the flow, to make less turns to the engines, can they move the plane? full load we are max 500kg. What engine displacement do I need?

and the rest of the data? Do we invent or do I have to change the batteries to the crystal ball?
However, for the hedonistic taste to give you an answer.. .
you must have the physical characteristics of the medium as starting data. diameter of wheels, weight of the vehicle, useful load, maximum theoretical slope you want to exceed, nominal speed. . .
from them you get the drive torque, to be applied to the wheels, and the rotation speed
at this point take the catalog of hydraulic engines that you like and choose the most suitable engine and, logically so, maximum valves and flow regulators (not taps, candalue!! ! ! )
continue the reasoning by calculating the pump and its motor, the tank, safety valves etc etc etc. etc.

but first, answer a question.. .
How are you going to dig? ? ? ?

 

[pierop85]

hello and thanks for the answers. I have a diesel engine from 359cc 3600 rpm max, 7.5cv and torque max to 2200 of 16.7nm, the pump that I have is a 25.8l/min to 1000 rpm max 2500 rpm working pressure 180bar and max pressure point 220bar, the wheels that I have diameter 50cm, the speed max k I would like to reach is 4/5kmh for the lowering, for the job I want to put a regulator I don't know what percentage they are but are reading

 

[MBT]

Good. .
Then throw down two calculations and then discuss it!

 

[pierop85]

here is the problem.... What do I do?

 

[MBT]

here is the problem.... What do I do?

How do you write first?

you must have the physical characteristics of the medium as starting data. diameter of wheels, weight of the vehicle, useful load, maximum theoretical slope you want to exceed, nominal speed. . .
from them you get the drive torque, to be applied to the wheels, and the rotation speed
at this point take the catalog of hydraulic engines that you like and choose the most suitable engine and, logically so, maximum valves and flow regulators (not taps, candalue!! ! ! )
continue the reasoning by calculating the pump and its motor, the tank, safety valves etc etc etc. etc.

a suggestion you can find here
http://www.eaton.com/ecm/groups/public/@pub/@eaton/@hyd/documents/content/pl_1323.pdfsaid in extreme synthesis.. .
you have the total weight of the vehicle (tara and payload), wheels diameter, slope.
suppose a friction coefficient that tells you the resistance of the medium according to the load
in practice, calculations how much you should "draw" the cart
knowing the diameter of the wheels, and knowing how many wheels are, calculate the torque to be applied to the wheels to have the above shot
Similarly, given the speed and diameter, you can also calculate the rotation speed of the wheels themselves

Meanwhile do this, then we choose the engine

 

[pierop85]

How do you write first?



a suggestion you can find here
http://www.eaton.com/ecm/groups/public/@pub/@eaton/@hyd/documents/content/pl_1323.pdfsaid in extreme synthesis.. .
you have the total weight of the vehicle (tara and payload), wheels diameter, slope.
suppose a friction coefficient that tells you the resistance of the medium according to the load
in practice, calculations how much you should "draw" the cart
knowing the diameter of the wheels, and knowing how many wheels are, calculate the torque to be applied to the wheels to have the above shot
Similarly, given the speed and diameter, you can also calculate the rotation speed of the wheels themselves

Meanwhile do this, then we choose the engine

At one point I have lost and I have understood some passages well, for example point 3 the breast and little thing about what?, point 5?, point 7 if nn I have changes I have to put1? and the speeds of the engine according to what I choose them?

 

[SOLID]

hello and thanks for the answers. I have a diesel engine from 359cc 3600 rpm max, 7.5cv and torque max to 2200 of 16.7nm, the pump that I have is a 25.8l/min to 1000 rpm max 2500 rpm working pressure 180bar and max pressure point 220bar, the wheels that I have diameter 50cm, the speed max k I would like to reach is 4/5kmh for the lowering, for the job I want to put a regulator I don't know what percentage they are but are reading

Hi piero,
for your orbital motor application between 120cc and 200 cc should be enough. the pump (I suppose to gears) seems too big for the diesel engine you have, you could only work with very low pressures, and also keep in mind that the machine to move to 5 km/h engines must turn to about 50 rpm, so the flow must be balanced according to the engine displacement.
Also since you have a single pump and not double more than two distributors, in my opinion, it is better to use a two-section monobloc distributor with maximum valve.

 

[MBT]

At one point I have lost and I have understood some passages well, for example point 3 the breast and little thing about what?, point 5?, point 7 if nn I have changes I have to put1? and the speeds of the engine according to what I choose them?

Are you referring to the easton calculation system?

I imagine that at point 3 is the sinus and little slope angle
5 in practice tells you that you have to calculate the residual shooting force you want to have. In summary, if your cart also has enough force to pull something else. I think it's not your case.
point 7 . says "number of driving motors", not number of marches! He wants to know how many engines they pull. how many wheel, in practice!! !

the number of engine turns you choose according to the speed of your cart, right?
cart speed is equal to the peripheral speed of the wheel.
known the diameter of the wheel, you know the angle speed, consequently the number of turns of the engine.

 

[pierop85]

Hi piero,
for your orbital motor application between 120cc and 200 cc should be enough. the pump (I suppose to gears) seems too big for the diesel engine you have, you could only work with very low pressures, and also keep in mind that the machine to move to 5 km/h engines must turn to about 50 rpm, so the flow must be balanced according to the engine displacement.
Also since you have a single pump and not double more than two distributors, in my opinion, it is better to use a two-section monobloc distributor with maximum valve.

for the pump is not a problem, can I replace it with a more suitable one, instead with the distributor monobloc I can turn both engines at the same turns?

 

[pierop85]

Are you referring to the easton calculation system?

I imagine that at point 3 is the sinus and little slope angle
5 in practice tells you that you have to calculate the residual shooting force you want to have. In summary, if your cart also has enough force to pull something else. I think it's not your case.
point 7 . says "number of driving motors", not number of marches! He wants to know how many engines they pull. how many wheel, in practice!! !

the number of engine turns you choose according to the speed of your cart, right?
cart speed is equal to the peripheral speed of the wheel.
known the diameter of the wheel, you know the angle speed, consequently the number of turns of the engine.

something I threw down hope they're accurate:
(point1) motor veiling: 42.4 rpm;
(point2) rotation resistance: 25 rr;
(point3) uphill traction effort: 50.75 gr;
(point4) acceleration force: 555 ago;
Total traction effort: 630.75 you;
(point7) hydraulic motor force: 78.84 t

at point 9 (r) what would be? wheel radius?

 

[MBT]

something I threw down hope they're accurate:
(point1) motor veiling: 42.4 rpm;
(point2) rotation resistance: 25 rr;
(point3) uphill traction effort: 50.75 gr;
(point4) acceleration force: 555 ago;
Total traction effort: 630.75 you;
(point7) hydraulic motor force: 78.84 t

at point 9 (r) what would be? wheel radius?

except I'm not checking the calculations, I'll take them for good
Maa... unit of measurement???? ? ? ?
because reasoning without doing can be useless, but doing without reasoning can be dangerous!!!!

At point 9 I imagine it's the wheel radius.

 

[MBT]

for the pump is not a problem, can I replace it with a more suitable one, instead with the distributor monobloc I can turn both engines at the same turns?

Oh, dear boy. .
You start having trouble.
I asked you at first:

but first, answer a question.. .
How are you going to dig? ? ? ?

 

[SOLID]

for the pump is not a problem, can I replace it with a more suitable one, instead with the distributor monobloc I can turn both engines at the same turns?

with the single block dispenser with two sections in parallel configuration you can use independently the two engines, but it is not said that they will turn at the same speed (depending on the difference of resistance that the wheels have on the ground and therefore the oil will go where it meets less resistance), to understand the effect is like that of a differential.

 

[pierop85]

Oh, dear boy. .
You start having trouble.
I asked you at first:

x turning using a motor at a time, for this must be independent

 

[pierop85]

with the single block dispenser with two sections in parallel configuration you can use independently the two engines, but it is not said that they will turn at the same speed (depending on the difference of resistance that the wheels have on the ground and therefore the oil will go where it meets less resistance), to understand the effect is like that of a differential.

even upstream a balancing valve?

 

[pierop85]

except I'm not checking the calculations, I'll take them for good
Maa... unit of measurement???? ? ? ?
because reasoning without doing can be useless, but doing without reasoning can be dangerous!!!!

At point 9 I imagine it's the wheel radius.

except point 1 that are turned, the rest is newton

 

[MBT]

x turning using a motor at a time, for this must be independent

How many wheels do you have??? Two, three or four? ? ?

 

[MBT]

with the single block dispenser with two sections in parallel configuration you can use independently the two engines, but it is not said that they will turn at the same speed (depending on the difference of resistance that the wheels have on the ground and therefore the oil will go where it meets less resistance), to understand the effect is like that of a differential.

even upstream a balancing valve?

in my humble opinion.. .
you have two solutions, if "the rest of the machine" allows you
a - after the pump and its maximum valves, mount a regulating proportional flow valve (which makes you as an accelerator) and then an adjustable flow divider (which acts as a "steel")
b solution - after the pump and its maximum valves, mountains two proportional flow regulator valves, one for each motor. in practice controls the cart with controls like a bobcat or an old-generation tank. a lever on the side. commanding them both in the same way, go straight, opening one more than the other steering on the right or left

all this if the mechanics allow you...