Thank you for your patience.for the rest and for explanations we are here. :biggrin:
in the sense that having only the ratio of reduction the nr of teeth of the pinion z1 you establish it and consequently for the z2 calculations multiplying z1*iThank you for your patience.
Let me get this straight. and if you can give me an example starting from 1/1.4(or another report)
I don't understand how to use formulas starting from 1/1.4
I want to understand! !
I've done, z1=20 z2=20*1.4=28in the sense that having only the ratio of reduction the nr of teeth of the pinion z1 you establish it and consequently for the z2 calculations multiplying z1*i
as mentioned by mechanicsmg you have to hypothesize power, number of incoming turns to size the input shaft and consequently determine how large the z1 pinion is needed
If by calculations/preliminary size you establish that your pinion z1 has 40 teeth (nb: randomly said value !!!) to determine z2 you just multiply z1 for transmission rapp., ie z2=z1*i = 40*1,4= 56 ie your pinion z2 will have 56 teeth
you are correct.I've done, z1=20 z2=20*1.4=28
the pinion 20 teeth and the other wheel 28.
the wheel with 28 teeth(enter shaft) will spin the pinion with 0.4 extra spin (exit shaft).is it right? ?
now for drawing..pignone:you are correct.
calculations are right, allow you to draw the wheel. Usually you do not choose the primitive diameter but the module and everything else turns around it. unified modules are 0.5 - 1 - 1.25 - 1.5 - 2 - 2.5 - 3 - 3.5 - 4 - 5 - 6 - 8 - 10 - 12 and beyond... so if in your case you have to increase or decrease you are appropriatenow for drawing..pignone:
m= primitive diameter/number of teeth=50 d prim.(choice by case)/20=2.5
Step=2.5*3,141(pgreek)=7.8
addendum=2.5
dedendum...
Axial length(8-12)=11*2.5=27.5
inner diameter=50-2.5*2.5=49.75
outer diameter=50+2*2.5=62.5
height dente=2.25*2.5=5.6
These are the calculations that allow me to draw the pinion.
repeating the same procedure with the 28 tooth wheel.
Is that correct?
primitive diameter=50 is it correct that I chose it?? in the drawing is the diameter that is between the point drawn lines of the toothed wheel? those lines that divide the view of the tooth. .
but the module according to what I choose it?calculations are right, allow you to draw the wheel. Usually you do not choose the primitive diameter but the module and everything else turns around it. unified modules are 0.5 - 1 - 1.25 - 1.5 - 2 - 2.5 - 3 - 3.5 - 4 - 5 - 6 - 8 - 10 - 12 and beyond... so if in your case you have to increase or decrease you are appropriate
the primitive diameter is that of ingracing the wheels, the ideal/real one depending on the cases, represented with line drawn point.
but have you already sized the bending, cutting and twisting shaft? have you already made the sizing and verification of the forces on the dentate wheels, the static and the fatigued one?
What school did you do before? Did you do that?but the module according to what I choose it?
My book doesn't tell me to check the forces of the dentate, static and dynamic wheels.. and what does it mean to dimensional the bending, cutting and twisting shaft? ?
thank you for the explanation..I did the high school class constructions of machines no...comanywhere in this course the prof did not explain anything about all this.I think I will study it in another course.I have the book technical industrial design, backincasa seems to me that it does not speak of this. .What school did you do before? Did you do that?
the shaft on which there is the toothed wheel, bound according to bearings, will have actions/reactions with the other wheel because of the power and number of turns in and with the load applied downstream. then on the tree there will be torque moment, cutting and bending. it is necessary to schematize as beams, to determine the most stressed section, to see with von mises the section and then possibly to correct the diameter of the tree itself. Moreover, the dynamic verification of the tree is used for fatigue testing (cuts, fittings, gorges etc). idem must be done on the dentate wheels that could break immediately (transfer of crash for static resistance failure and then undersized) or to surface wear or bending after medium high cycles (see pitting and tooth bending).
the module or the hypotizzi and do static and dynamic verification, or presize it statically using the static lewis report or according to one 8862 through the synthetic surface factor reported to pressure and with the synthetic factor of the tooth foot reported to bending. then check dynamics to see if it is ok.
Your decision is very courageous! Good! Since things are like this, you have to try to give a correct proportion to your design. Surely on the return home there will be a parallel axle reducer or his some other book and surely to have an idea of proportions you will find the suitable material. Since a real dimensioning has not yet taught you, try to make the most of the drawing book regarding the data of the toothed wheels, choice of the bearing, tolerances and finishes.thank you for the explanation..I did the high school class constructions of machines no...comanywhere in this course the prof did not explain anything about all this.I think I will study it in another course.I have the book technical industrial design, backincasa seems to me that it does not speak of this. .
but the motorcycle entry shaft should not be the one to which the smaller wheel is attached, so with the least number of teeth? otherwise it does not reduce.I've done, z1=20 z2=20*1.4=28
the pinion 20 teeth and the other wheel 28.
the wheel with 28 teeth(enter shaft) will spin the pinion with 0.4 extra spin (exit shaft).is it right? ?
ratio 1:1.4 is the transmission ratio such as i = z2/z1 = n1/n2. may also not be a reducer but a multiplier of turns. in this case n1 = 1 lap and n2 = 1.4 laps, as I understood it by consulting the vademecum for designers and technicians and other sources, by scruple.but the motorcycle entry shaft should not be the one to which the smaller wheel is attached, so with the least number of teeth? otherwise it does not reduce.
Besides the design of the reducer, in the exercise I have to redesign it and quote it, but some of my colleagues told me that you have to quote only the bigger wheel and not all the reducer and not even the pinion. why?just a few ideas since I was asked in mp, not to make the same mistakes and the same considerations.
- piece sprocket means tree with cut in single piece the pinion.
- caletta wheel with tongue means tree + wheel + tongue
- reducers have seals etc. this reducer already analyzed and all the recommendations in the development phase
pdf layout of concepts.
I would propose to read carefully the text your teacher gave you. I am also normdotated as you, so I can only read the text ... I can give my synthetic interpretation:Besides the design of the reducer, in the exercise I have to redesign it and quote it, but some of my colleagues told me that you have to quote only the bigger wheel and not all the reducer and not even the pinion. why?
and then in the registration table I have to write the various calculations of the two wheels or only one?