motor dimensioning for preheating roller

[bencre]

Good morning to all,
My problem today is the verification of a reducer to bring a cylinder-vapore in rotation.
data are:
vinyl =0 m/1
vfinal=300 m/1' (which then would be the maximum speed of the line)
m cylinder = 1090 kg
øest=900 mm sp.12 mm
t (time to get from 0 to 300 m/1')=60 seconds
the gearbox =20.329
ix (calculated by solidworks)=159 kg m2

I'm afraid I'm not an engineer, so it's definitely a trivial calculation for you, but I've been counting since yesterday, and I've been out of the most absurd results! !
I used canonical formulas, but something doesn't fit.
please tell me the couple I need out of the gearbox and the engine power.
or better could you tell me the correct formulas to use?
Thank you very much
yellow

 

[MBT]

Let's do this.
you present your accounts, nonsense including... and then let's just go along

 

[Enigma]

Let's do this.
you present your accounts, nonsense including... and then let's just go along

I fully agree with my colleague (of forums). . .

enigma

 

[bencre]

Then. .
from v=300 m/1' and from øest 900 mm embroidery that omega w=2 lazy n /60 =11.1 rad/sec
after how utilzzerei formulas m (moment) = i (moment inertia) x a (which should be angular acceleration? )
p (power) = mt x w
Do I have any doubts about it?? ?

 

[bencre]

I mean. . .
a=w/t where w=2 lazy n /60 and t=1/f and then in my case 0.568? ? ?

 

[meccanicamg]

I would say that it is not very difficult to make these accounts.
formulas are always the same. the only thing to evaluate is the moment reduced to the engine that is what must be accelerated from zero to 300 m/min.
I attach the calculation card I used and see the comparison.

 

[bencre]

thank you for the solution of the problem...0.33 kw!
but I wanted to know if you could inhydrate me the formulas you used, to check where I was wrong!
then once the problem is clarified it is possible to have the calculation card used by mechanicalmg for future measurements? ? ?
Thank you very much

 

[bencre]

Please, gentlemen, help me understand where I'm wrong!
I also renew my request to have the calculation card for next applications, but what I most like and understand where or what formula I was bouncing.
Thank you.

 

[meccanicamg]

probably what is wrong is the calculation of the reduced inertia to the motor that is j'=jcarico/i^2 where i is the reduction ratio of the mechanical reducer interposed.
or wrong the fact that cm=awm*j' where cm is the engine torque calculated as the product between awm that is the angular acceleration motor and I that is the moment of inertia reduced to the motor.
or the fact that acceleration a=wm/t where wm is the angular velocity of final rotation (see that the initial one is zero) and t acceleration time.
the engine power wm=cm*wm is given by the product cm that is the motor couple and the motor angle speed wm.

then the value you get (e.g. 0.33kw) is multiplied by an appropriate service factor so it will become bigger to ensure that the application can actually deliver what it takes.
eventually increase the engine for the speech of mechanical and electrical returns.