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tolerance chain and bearing width

  • Thread starter Thread starter Vitreo
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Vitreo

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Good morning, everyone. I'm recovering the "theory" of the tolerance chains because lately I have to deal with applications where I have to evaluate the maximum game and the minimum game in a small set mounted.

in a set in which fixed (with two seeger at the ends) a shaft supported between two bearings, I have difficulty in finding information on how to treat the axial encumbrance of a radial bearing, the x distance in the image I attach, ie the distance between the shouldering of the tube and the internal support of the seeger.
I would say that:
x=b ± C
where:
b is the nominal bearing width
c is the inner axial game of the bearing.
But I wanted to ask those who are more familiar with bearings.
Thank you in advance.
 

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First of all you should know the degree of precision of the bearing, then you will realize that the construction tolerances of a bearing are of the order of microm and are almost influential if you consider that the seat of the seeger is of the order of 0.15 mm on a shaft diameter 20.
However, the constrictive tolerances of the bearings find them on this page
 
on the page you linked, in fact if I go to read the "Table 1", corresponding to the tolerance values for normal class bearings, I read a series of values.
it seems to me that the tolerance on the width of the rings is tδbs and, for a bearing with hole that goes 10 to 18mm, admits a lower shock of 120 microns, that is 0.12mm.
 
If you want to remove the game and bring the maximum capacity of the seeger, interpose a live spacer to be shaved to the assembly.
 
forgives the banality of the question: Why does the financier have to be alive?
I think it's useful to maximise the area, which is already unequal, of support between space and seeger. But I don't know for sure.
 
in your sketch you do not see all the assembly, but normally to avoid unnecessary and harmful axial pressures to the bearing itself, it should give 0.1 /0.2 mm of play.
so x = b +0.1 /+0.2
 
forgives the banality of the question: Why does the financier have to be alive?
I think it's useful to maximise the area, which is already unequal, of support between space and seeger. But I don't know for sure.
If you go to take a good manual or catalog that speaks of seeger holding the bearings, it will be explained that the bearing radius is large and therefore does not make the seeger rest in a complete way. for this reason, rings or spacers are realized that are alive or little more precisely to be able to support all the seeger on the spacer.... which will have diameter sufficiently larger.

for this purpose they invented the rings religion 988 that there are various diameters and various calibrated thicknesses.Screenshot_20221220_192532.jpgif you do not correctly support the seeger with a spacer with edges not beveled or almost, you have the rotation of the seeger ring and therefore a sensitive loss of load capacity.Screenshot_20221220_192739.jpgas you can see from the appropriate calculation, you have less load capacity with large real radius.
Screenshot_20221220_193603.webpScreenshot_20221220_193650.webp
 
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